#Bash script get file path code#
In that case above code prints the location of the link instead the original file. DIR (cd ' (dirname ' (readlink '0' echo '0')')' & pwd) This is because the symlink or the script behind can both be called by users.
#Bash script get file path free#
Have I missed anything? Do you have any feedback or questions? Have you noticed a mistake/typo? Feel free to comment below and I’ll answer ASAP! Thanks for reading. When I need to get path to the script file inside script itself I use something like this: dirname 0 that works file until I call the script through sym link to it. Value of ABS_SCRIPT_PATH: /home/matheus/script_dir.shĪnd voilà! You can now use the above lines in your tooling scripts. Similarly, we also look at the $"įurthermore, when I saved the above block to the file script_dir.sh in my home directory, and executed it with the following commands: # make the script executable When I run the above script it gives me an error: grab Finance -bash: get: command not found. My script: /bin/bash cat /usr/bin/data/server grep 1 done. Like if I enter grab Finance (where grab is a word) it will show as below. Unsurprisingly, this is probably the most popular option out there, as it’s very simple to use and it’s fairly well defined in non-bash shells. Preparing script like below to have these data by entering one word instead of path. First.sh Go to top Use of echo command: You can use echo command with various options.
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Long story short, we rely on two different shell variables that contain (the relative) path of the script being executed.įirstly, we will look at the variable $0, which should contain the path of the script being executed. One way is by using bash command and another is by setting execute permission to bash file and run the file.
Leaf-T1-FD-R2_S29_L001,/users/3052771/sharedscratch/Amplicon_data_july_2019/PN0086C_16S-137179427/Amplicon_2019_RNAseq/Leaf-T1-FD-R2_S29_L001_R2_: the best way to get the path of a shell script while writing an unzipping script! Two Different Ways To Get The Path Of A Script: $0 Vs $BASH_SOURCE Will return: sample-id,absolute-filepath,direction SampleR2=$(echo $R2 | sed 's/_R2_//')Ĭan you check by printing out fileR2 after you did fileR2=$(echo $fileR1 | sed 's/R1/R2/')?Īlso, you can add _R1_ when you use basename. # PATH to directory holding files, no trailing slash! I am using below script to write the sample name, followed by path of the file and then for R1 it write forward and for R2 it writes reverse: but some of the file it do not write correctly, could you please suggest what is the problem: sample-id,absolute-filepath,direction
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